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1/6^-3x-2=36^x+1
We move all terms to the left:
1/6^-3x-2-(36^x+1)=0
We get rid of parentheses
-3x-36^x-1-2+1/6^=0
We multiply all the terms by the denominator
-3x*6^-36^x*6^+1-1*6^-2*6^=0
We add all the numbers together, and all the variables
-3x*6^-36^x*6^=0
Wy multiply elements
-18x^2-216x^2=0
We add all the numbers together, and all the variables
-234x^2=0
a = -234; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-234)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-468}=0$
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